Leetcode 2347 Best Poker Hand Solution in Java | Hindi Coding Community

 

You are given an integer array ranks and a character array suits. You have 5 cards where the ith card has a rank of ranks[i] and a suit of suits[i].

The following are the types of poker hands you can make from best to worst:

1. "Flush": Five cards of the same suit.
2. "Three of a Kind": Three cards of the same rank.
3. "Pair": Two cards of the same rank.
4. "High Card": Any single card.

Return a string representing the best type of poker hand you can make with the given cards.

Note that the return values are case-sensitive.

 

Example 1:

Input: ranks = [13,2,3,1,9], suits = ["a","a","a","a","a"]
Output: "Flush"
Explanation: The hand with all the cards consists of 5 cards with the same suit, so we have a "Flush".

Example 2:

Input: ranks = [4,4,2,4,4], suits = ["d","a","a","b","c"]
Output: "Three of a Kind"
Explanation: The hand with the first, second, and fourth card consists of 3 cards with the same rank, so we have a "Three of a Kind".
Note that we could also make a "Pair" hand but "Three of a Kind" is a better hand.
Also note that other cards could be used to make the "Three of a Kind" hand.

Example 3:

Input: ranks = [10,10,2,12,9], suits = ["a","b","c","a","d"]
Output: "Pair"
Explanation: The hand with the first and second card consists of 2 cards with the same rank, so we have a "Pair".
Note that we cannot make a "Flush" or a "Three of a Kind".

 

Constraints:

• ranks.length == suits.length == 5
• 1 <= ranks[i] <= 13
• 'a' <= suits[i] <= 'd'
• No two cards have the same rank and suit.

Java Code :

public String bestHand(int[] ranks, char[] suits) {

Map<Integer, Integer> rankmap = new HashMap<>();

Map<Character, Integer> suitmap = new HashMap<>();

for(int r: ranks){

rankmap.put(r, rankmap.getOrDefault(r, 0) + 1);

}

for(char s: suits){

suitmap.put(s, suitmap.getOrDefault(s, 0) + 1);

}

// Being smart about the conditons

if(suitmap.containsValue(5)){

return "Flush";

}

if(rankmap.containsValue(5) || rankmap.containsValue(4) || rankmap.containsValue(3)){

return "Three of a Kind";

}

if(rankmap.containsValue(2)){

return "Pair";

}

return "High Card";

}