Leetcode 2 add two numbers Solution in c++ | Hindi Coding Community

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Add two numbers leetcode

 You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

You have to write a code for this problem. We have implemented the code in c++ Language. Hindi Coding Community provides you the best solutions of this problem. 

 

Example 1:

Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.

Example 2:

Input: l1 = [0], l2 = [0]
Output: [0]

Example 3:

Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]

 

Constraints:

  • The number of nodes in each linked list is in the range [1, 100].
  • 0 <= Node.val <= 9
  • It is guaranteed that the list represents a number that does not have leading zeros.

class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode* dummy=new ListNode();
ListNode* temp=dummy;
int carry=0;
while(l1!=NULL || l2!=NULL || carry){
int sum=0;
if(l1!=NULL){
sum+=l1->val;
l1=l1->next;
}
if(l2!=NULL){
sum+=l2->val;
l2=l2->next;
}
sum+=carry;
carry=sum/10;
ListNode* newnode=new ListNode(sum%10);
temp->next=newnode;
temp=temp->next;
}
return dummy->next;
}
};


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