Leetcode 7 Reverse Integer Solution in Java | Hindi Coding Community

 Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

 

Example 1:

Input: x = 123

Output: 321

Example 2:

Input: x = -123

Output: -321

Example 3:

Input: x = 120

Output: 21

public int reverse(int x) {

long rev= 0;

while( x != 0){

rev= rev*10 + x % 10;

x= x/10;

if( rev > Integer.MAX_VALUE || rev < Integer.MIN_VALUE)

return 0;

}

return (int) rev;

}

}