Leetcode 34 Find First and Last Position of Element in Sorted Array Solution in java | Hindi Coding Community

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Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value.

If target is not found in the array, return [-1, -1].

You must write an algorithm with O(log n) runtime complexity.


Example 1:


Input: nums = [5,7,7,8,8,10], target = 8

Output: [3,4]

Example 2:


Input: nums = [5,7,7,8,8,10], target = 6

Output: [-1,-1]




public int[] searchRange(int[] nums, int target) {
int[] res = {-1, -1};
int lo = 0, hi = nums.length - 1;

while(nums[lo] < nums[hi]) {
int mid = lo + (hi - lo)/2;
if(nums[mid] > target) {
hi = mid - 1;
} else if(nums[mid] < target) {
lo = mid + 1;
} else {
if(nums[lo] == nums[mid]) {
hi--;
}else {
lo++;
}
}
}
if(nums[lo] == nums[hi] && nums[lo]== target) {
res[0] = lo;
res[1] = hi;
}
return res;
}


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