Pow(x, n) Leetcode Solution in c++ | Hindi Coding Community

 

Implement pow(x, n), which calculates x raised to the power n (i.e., xn).

Example 1:

Input: x = 2.00000, n = 10

Output: 1024.00000

class Solution {

public:

double myPow(double x, int n) {

if(n==0 || x==1)

return 1;

double val= myPow(x,n/2);

val*=val;

if(n%2==0)

return val;

else{

if(n<0)

return val*(1/x);

return val*x;

}

}

};