Convert JSON String to Object in C#

 

Convert JSON String to Object in C#

JSON (JavaScript Object Notation) is a lightweight and widely used data interchange format that is easy to read and write. It is based on a subset of the JavaScript programming language, but is language-independent and can be used with any programming language. In C#, it is common to convert a JSON string to an object for further processing. In this blog post, we will discuss how to convert a JSON string to an object in C#.

1. Parse JSON using JSON.NET

JSON.NET is a popular third-party library for working with JSON in C#. It provides a simple and efficient way to convert a JSON string to an object. To use JSON.NET, you need to install the Newtonsoft.Json NuGet package. Once installed, you can use the JsonConvert class to deserialize the JSON string into an object.

Here's an example:

using Newtonsoft.Json;

string jsonString = "{\"name\":\"John\",\"age\":30,\"city\":\"New York\"}";

var obj = JsonConvert.DeserializeObject(jsonString);

JSON (JavaScript Object Notation) is a lightweight and widely used data interchange format that is easy to read and write. It is based on a subset of the JavaScript programming language, but is language-independent and can be used with any programming language. In C#, it is common to convert a JSON string to an object for further processing. In this blog post, we will discuss how to convert a JSON string to an object in C#.

2. Convert JSON using System.Text.Json

Starting from .NET Core 3.0, C# includes a built-in JSON API in the System.Text.Json namespace. It is lightweight, fast, and is optimized for performance. Here's an example:

using System.Text.Json;

string jsonString = "{\"name\":\"John\",\"age\":30,\"city\":\"New York\"}";

var obj = JsonSerializer.Deserialize<object>(jsonString);

In this example, we have a JSON string that represents an object with three properties: name, age, and city. We use the JsonSerializer.Deserialize method to deserialize the JSON string into an object.

3. Deserialize JSON to a strongly-typed object

The examples above deserialize the JSON string into an object of type "object", which is not very useful. To get the full benefits of working with JSON in C#, it's best to deserialize the JSON string into a strongly-typed object.

Here's an example using JSON.NET:

using Newtonsoft.Json;

public class Person

{

    public string Name { get; set; }

    public int Age { get; set; }

    public string City { get; set; }

}

string jsonString = "{\"Name\":\"John\",\"Age\":30,\"City\":\"New York\"}";

var obj = JsonConvert.DeserializeObject<Person>(jsonString);

In this example, we have a Person class with three properties: Name, Age, and City. We use the JsonConvert.DeserializeObject method to deserialize the JSON string into a Person object.

Here's an example using System.Text.Json:

using System.Text.Json;

public class Person

{

    public string Name { get; set; }

    public int Age { get; set; }

    public string City { get; set; }

}

string jsonString = "{\"Name\":\"John\",\"Age\":30,\"City\":\"New York\"}";

var obj = JsonSerializer.Deserialize<Person>(jsonString);

In this example, we have a Person class with three properties: Name, Age, and City. We use the JsonSerializer.Deserialize method to deserialize the JSON string into a Person object.

Converting a JSON string to an object in C# is a common task when working with APIs or data from external sources. In this blog post, we discussed how to convert a JSON string to an object using JSON.NET and the built-in JSON API in .NET Core. We also discussed how to deserialize the JSON string into a strongly-typed object, which is the recommended approach.