Banker's Algorithm in Operating System (OS)
The Banker's Algorithm is a resource allocation and deadlock avoidance algorithm used in operating systems to allocate resources to processes in such a way that it prevents deadlock. It was developed by Edsger Dijkstra in 1965 and is often used in systems that have multiple processes competing for limited resources.
Problem Overview:
In a system with multiple processes, resources (like memory, CPU time, or I/O devices) are limited. The Banker's Algorithm ensures that resources are allocated safely and efficiently, avoiding deadlock situations by checking whether a requested resource allocation can lead to a safe state or not.
A safe state is a situation where there exists at least one sequence of processes that can finish executing without causing any process to wait indefinitely for resources. If the system is in a safe state, resources can be allocated to processes in such a way that all processes will eventually complete without leading to deadlock.
Basic Concepts:
Resources: The system has a finite set of resources (e.g., CPU time, memory, printers, etc.), and these resources are either allocated to processes or available for allocation.
Process: Each process in the system requires a certain number of resources to complete its execution.
Allocation: The set of resources currently allocated to a process.
Max: The maximum number of resources a process may require to complete.
Available: The number of resources that are currently available for allocation to processes.
Need: The remaining number of resources required by a process to finish its execution. It can be calculated as:
Algorithm Overview:
The Banker's Algorithm works by simulating resource allocation for each request and checking whether the system will remain in a safe state after the allocation.
The algorithm consists of two main steps:
Requesting Resources: A process may request resources, which is checked to see if the request can be granted immediately without exceeding the available resources.
Safety Check: The system checks whether, after allocating the requested resources, the system remains in a safe state. The safety check involves simulating the allocation and determining if there exists a sequence of processes that can be completed.
Steps Involved:
Process Request: When a process requests resources, the Banker's Algorithm first checks if the request is less than or equal to the available resources. If the request exceeds the available resources, the process must wait.
Temporary Allocation: If the request is valid, the algorithm temporarily allocates the resources, adjusting the available resources, the allocation table, and the need table.
Safety Check: The algorithm then checks if there exists a sequence of processes that can execute with the remaining resources. If a safe sequence exists, the resources are allocated. If no such sequence exists, the process must wait, and the resources are not allocated.
Rollback: If the system enters an unsafe state, the resources are rolled back, and the process is forced to wait.
Banker's Algorithm Safety Check (Step-by-Step):
Simulate resource allocation: Temporarily allocate the requested resources to the process and update the available resources.
Work and Finish: Create two vectors,
Work
andFinish
. TheWork
vector represents the available resources, and theFinish
vector represents whether a process has finished.- Initialize
Work
with the available resources. - Initialize
Finish
for each process asfalse
.
- Initialize
Check for a Safe Sequence:
- Find a process
i
whoseFinish[i]
isfalse
and whose Need is less than or equal to theWork
vector (i.e., the process can finish). - If such a process is found, mark
Finish[i] = true
, release the resources allocated toi
, and add them toWork
. - Repeat the above step until all processes are marked as
finished
or no process can proceed.
- Find a process
Decision:
- If all processes can be finished (
Finish[i] = true
for alli
), then the state is safe, and the requested resources are allocated. - If no such sequence exists, the system is in an unsafe state, and the request is denied.
- If all processes can be finished (
Example of Banker's Algorithm:
Consider a system with 3 types of resources (A, B, C) and 5 processes (P1 to P5).
Process | Max Resources (A, B, C) | Allocation (A, B, C) | Need (A, B, C) |
---|---|---|---|
P1 | (7, 5, 3) | (2, 3, 2) | (5, 2, 1) |
P2 | (3, 2, 2) | (2, 1, 1) | (1, 1, 1) |
P3 | (9, 0, 2) | (3, 2, 2) | (6, 0, 0) |
P4 | (2, 2, 2) | (2, 1, 1) | (0, 1, 1) |
P5 | (4, 3, 3) | (0, 0, 2) | (4, 3, 1) |
Available Resources: (3, 3, 2)
When a process requests resources, the Banker's Algorithm checks if the system can still be in a safe state after the request. If it is safe, the allocation proceeds; if not, the process must wait.
Advantages of the Banker's Algorithm:
- Deadlock Prevention: The algorithm ensures that the system remains in a safe state, thereby preventing deadlock.
- Resource Efficiency: The algorithm provides a way to maximize resource usage without exceeding available resources.
- Dynamic Resource Allocation: It can handle dynamic resource allocation and deallocation.
Disadvantages:
- Complexity: The Banker's Algorithm can be computationally expensive due to the need for checking the safety of each resource allocation.
- Overhead: The algorithm requires maintaining and frequently updating several tables (e.g., allocation, need, available), which can incur overhead.
- Limited Applicability: The algorithm is only suitable for systems with known maximum resource requirements, which may not be practical in all real-world scenarios.
Real-World Use Cases:
- Database Management Systems: DBMS often use a similar approach to manage concurrent access to databases and prevent deadlock.
- Operating Systems: OSs use resource management techniques inspired by the Banker's Algorithm to allocate resources like memory and CPU time.
- Distributed Systems: In systems with multiple nodes, the Banker's Algorithm can help in preventing resource conflicts and deadlock during resource allocation.
Example of the Banker's Algorithm
Let’s walk through a detailed example of the Banker’s Algorithm for deadlock avoidance in an operating system. We'll consider a system with three types of resources and five processes. The goal is to determine whether a process request can be granted while ensuring the system remains in a safe state.
System Setup:
Resources:
- 3 types of resources (A, B, C)
- Available resources:
(3, 3, 2)
Processes (P1, P2, P3, P4, P5):
Resources:
- 3 types of resources (A, B, C)
- Available resources:
(3, 3, 2)
Processes (P1, P2, P3, P4, P5):
Process | Max Resources (A, B, C) | Allocation (A, B, C) | Need (A, B, C) |
---|---|---|---|
P1 | (7, 5, 3) | (2, 3, 2) | (5, 2, 1) |
P2 | (3, 2, 2) | (2, 1, 1) | (1, 1, 1) |
P3 | (9, 0, 2) | (3, 2, 2) | (6, 0, 0) |
P4 | (2, 2, 2) | (2, 1, 1) | (0, 1, 1) |
P5 | (4, 3, 3) | (0, 0, 2) | (4, 3, 1) |
- Available Resources:
(3, 3, 2)
Steps to Allocate Resources Using Banker's Algorithm:
Initial Setup:
- Max table: This is the maximum demand for resources by each process.
- Allocation table: This is the number of resources currently allocated to each process.
- Need table: This is the difference between the maximum resources required and the current allocation. It represents the remaining resources each process needs to complete.
Request:
Suppose P1 requests (1, 0, 2)
resources. We need to check if the request can be safely granted.
- Requested resources by P1:
(1, 0, 2)
- Available resources:
(3, 3, 2)
Since the request (1, 0, 2)
is less than or equal to the available resources (3, 3, 2)
, the request can be considered for allocation.
Temporary Allocation:
Allocate the requested resources to P1 temporarily:
- New available resources:
(3, 3, 2) - (1, 0, 2) = (2, 3, 0)
- New allocation for P1:
(2, 3, 2) + (1, 0, 2) = (3, 3, 4)
- New need for P1:
(5, 2, 1) - (1, 0, 2) = (4, 2, 1)
Safety Check:
Now, we need to check if the system remains in a safe state after this allocation.
Start by checking if any process can finish with the available resources (2, 3, 0)
.
Initialize Work = (2, 3, 0)
and Finish = [false, false, false, false, false]
.
Step 1: Check P1:
- Need for P1:
(4, 2, 1)
Need
of P1 is greater than Work
, so P1 cannot finish yet.
Step 2: Check P2:
- Need for P2:
(1, 1, 1)
Need
of P2 is less than or equal to Work
, so P2 can finish.- After P2 finishes, it releases its allocated resources
(2, 1, 1)
, and now Work = (2, 3, 0) + (2, 1, 1) = (4, 4, 1)
.
Step 3: Check P4:
- Need for P4:
(0, 1, 1)
Need
of P4 is less than or equal to Work
, so P4 can finish.- After P4 finishes, it releases its allocated resources
(2, 1, 1)
, and now Work = (4, 4, 1) + (2, 1, 1) = (6, 5, 2)
.
Step 4: Check P5:
- Need for P5:
(4, 3, 1)
Need
of P5 is less than or equal to Work
, so P5 can finish.- After P5 finishes, it releases its allocated resources
(0, 0, 2)
, and now Work = (6, 5, 2) + (0, 0, 2) = (6, 5, 4)
.
Step 5: Check P3:
- Need for P3:
(6, 0, 0)
Need
of P3 is less than or equal to Work
, so P3 can finish.- After P3 finishes, it releases its allocated resources
(3, 2, 2)
, and now Work = (6, 5, 4) + (3, 2, 2) = (9, 7, 6)
.
Step 6: Check P1:
- Need for P1:
(4, 2, 1)
Need
of P1 is less than or equal to Work
, so P1 can finish.- After P1 finishes, it releases its allocated resources
(3, 3, 2)
, and now Work = (9, 7, 6) + (3, 3, 2) = (12, 10, 8)
.
Conclusion:
Since all processes can eventually finish in a safe sequence, the system remains in a safe state after granting P1's request. The request is granted.
Initial Setup:
- Max table: This is the maximum demand for resources by each process.
- Allocation table: This is the number of resources currently allocated to each process.
- Need table: This is the difference between the maximum resources required and the current allocation. It represents the remaining resources each process needs to complete.
Request:
Suppose P1 requests (1, 0, 2)
resources. We need to check if the request can be safely granted.
- Requested resources by P1:
(1, 0, 2)
- Available resources:
(3, 3, 2)
Since the request (1, 0, 2)
is less than or equal to the available resources (3, 3, 2)
, the request can be considered for allocation.
Temporary Allocation: Allocate the requested resources to P1 temporarily:
- New available resources:
(3, 3, 2) - (1, 0, 2) = (2, 3, 0)
- New allocation for P1:
(2, 3, 2) + (1, 0, 2) = (3, 3, 4)
- New need for P1:
(5, 2, 1) - (1, 0, 2) = (4, 2, 1)
Safety Check: Now, we need to check if the system remains in a safe state after this allocation.
Start by checking if any process can finish with the available resources
(2, 3, 0)
.Initialize
Work = (2, 3, 0)
andFinish = [false, false, false, false, false]
.Step 1: Check P1:
- Need for P1:
(4, 2, 1)
Need
of P1 is greater thanWork
, so P1 cannot finish yet.
- Need for P1:
Step 2: Check P2:
- Need for P2:
(1, 1, 1)
Need
of P2 is less than or equal toWork
, so P2 can finish.- After P2 finishes, it releases its allocated resources
(2, 1, 1)
, and nowWork = (2, 3, 0) + (2, 1, 1) = (4, 4, 1)
.
- Need for P2:
Step 3: Check P4:
- Need for P4:
(0, 1, 1)
Need
of P4 is less than or equal toWork
, so P4 can finish.- After P4 finishes, it releases its allocated resources
(2, 1, 1)
, and nowWork = (4, 4, 1) + (2, 1, 1) = (6, 5, 2)
.
- Need for P4:
Step 4: Check P5:
- Need for P5:
(4, 3, 1)
Need
of P5 is less than or equal toWork
, so P5 can finish.- After P5 finishes, it releases its allocated resources
(0, 0, 2)
, and nowWork = (6, 5, 2) + (0, 0, 2) = (6, 5, 4)
.
- Need for P5:
Step 5: Check P3:
- Need for P3:
(6, 0, 0)
Need
of P3 is less than or equal toWork
, so P3 can finish.- After P3 finishes, it releases its allocated resources
(3, 2, 2)
, and nowWork = (6, 5, 4) + (3, 2, 2) = (9, 7, 6)
.
- Need for P3:
Step 6: Check P1:
- Need for P1:
(4, 2, 1)
Need
of P1 is less than or equal toWork
, so P1 can finish.- After P1 finishes, it releases its allocated resources
(3, 3, 2)
, and nowWork = (9, 7, 6) + (3, 3, 2) = (12, 10, 8)
.
- Need for P1:
Conclusion: Since all processes can eventually finish in a safe sequence, the system remains in a safe state after granting P1's request. The request is granted.
Final State:
- Available resources:
(12, 10, 8)
- Allocation table and Need table will reflect the changes after the allocation.
(12, 10, 8)
Summary:
The Banker's Algorithm safely allocated resources to process P1 after checking whether the system could remain in a safe state. The algorithm ensured that deadlock was avoided by verifying that a sequence of processes could finish and release resources.
This is a simplified example to demonstrate how the Banker's Algorithm works. In real systems, the number of resources and processes could be much larger, but the principles remain the same.
The Banker's Algorithm is an important deadlock avoidance algorithm that ensures safe resource allocation in systems with multiple processes and limited resources. By checking whether resource requests can lead to a safe state, it helps in maintaining the stability of the system and avoiding deadlock.